20t-5*t^2/2=30

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Solution for 20t-5*t^2/2=30 equation: 


t in (-oo:+oo)

20*t-((5*t^2)/2) = 30 // - 30

20*t-((5*t^2)/2)-30 = 0

(-5/2)*t^2+20*t-30 = 0

20*t-5/2*t^2-30 = 0

DELTA = 20^2-(-30*(-5/2)*4)

DELTA = 100

DELTA > 0

t = (100^(1/2)-20)/(-5/2*2) or t = (-100^(1/2)-20)/(-5/2*2)

t = 2 or t = 6

t in { 2, 6 }

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